ada yang bisaaaaaaaaa
x1, x2 = -3, - 1/2
Penjelasan dengan langkah-langkah:
[tex] \sf 2 {x}^{2} + 7x + 3 = 0 \\ \sf 2 {x}^{2} + 6x + x + 3 = 0 \: \: \: \: \: \: \: \: \\ \sf 2x(x + 3) + x + 3 = 0 \: \: \: \: \: \: \: \: \: \\ \sf (x + 3)(2x + 1) = 0 \: \: \: \: \: [/tex]
-
x + 3 = 0
x = -3
-
2x + 1 = 0
x = -1
x = - 1/2
-
[answer.2.content]
